4048891811(base 10) = F1552FA3(base 16).
2114112(base 8) = 563274(base 10).
52E4F03B + 902DC47 = 5BE7CC82(base 16)
2532(base 6) =
2*63 + 5*62 + 3*61 + 2*60
2*216 + 5*36 + 3*6 + 2 = 432 + 180 + 18 + 2 = 632(base
10)
Using the algorithm from class, 349/6 = 58 + 1/6
58/6 = 9 + 4/6
9/6 = 1 + 3/6
1/6 = 0 + 1/6
So 349(base 10) should equal
1341(base 6).
(checking our answer, indeed 349 = 1*216 + 3*36 + 4*6 + 1 = 216+108+24+1)
| 1 | 1 | 1 | ||||||
| 4 | 3 | 0 | 2 | 4 | 6 | 3 | (base 7) | |
| + | 5 | 1 | 3 | 4 | 6 | 0 | (base 7) | |
| - | - | - | - | - | - | - | - | |
| 5 | 1 | 1 | 6 | 2 | 5 | 3 | (base 7) |
| 1 | 1 | 1 | 1 | ||||||||
| 9 | 4 | A | 2 | B | 2 | (base 12) | |||||
| + | 1 | 5 | 0 | 5 | A | 6 | 9 | (base 12) | |||
| - | - | - | - | - | - | - | - | - | - | - | - |
| 2 | 2 | 5 | 4 | 1 | 5 | B | (base 12) |
In short,
6(base 16)=12(base 4)
F(base 16)=33(base 4)
9(base 16)=21(base 4)
C(base 16)=30(base 4)
3(base 16)=03(base 4)
If you want to better understand the math, notice that
6*164 = 6*48 = (1*49 + 2*48)
15*164 = 15*48 = (3*49 + 3*48)
and so on