Solution

Number Systems and Arithmetic

Problems to be Submitted (20 points)

  1. (2 points)

    4048891811(base 10) = F1552FA3(base 16).

  2. (2 points)

    2114112(base 8) = 563274(base 10).

  3. (2 points)

    52E4F03B + 902DC47 = 5BE7CC82(base 16)

  4. (3 points)

    2532(base 6) = 2*63 + 5*62 + 3*61 + 2*60
    2*216 + 5*36 + 3*6 + 2 = 432 + 180 + 18 + 2 = 632(base 10)

  5. (3 points)

    Using the algorithm from class, 349/6 = 58 + 1/6
    58/6 = 9 + 4/6
    9/6 = 1 + 3/6
    1/6 = 0 + 1/6
    So 349(base 10) should equal 1341(base 6).

    (checking our answer, indeed 349 = 1*216 + 3*36 + 4*6 + 1 = 216+108+24+1)

  6. (4 points)

    1 1 1
    4 3 0 2 4 6 3  (base 7)
    + 5 1 3 4 6 0  (base 7)
    - - - - - - - -
    5 1 1 6 2 5 3  (base 7)

  7. (4 points)

    1 1 1 1
    9 4 A 2 B 2  (base 12)
    + 1 5 0 5 A 6 9  (base 12)
    - - - - - - - - - - - -
    2 2 5 4 1 5 B  (base 12)


Extra Credit (2 points)

6F9C3(base 16) = 1233213003(base 4)

In short,
6(base 16)=12(base 4)
F(base 16)=33(base 4)
9(base 16)=21(base 4)
C(base 16)=30(base 4)
3(base 16)=03(base 4)

If you want to better understand the math, notice that
6*164 = 6*48 = (1*49 + 2*48)
15*164 = 15*48 = (3*49 + 3*48)
and so on


Last modified: Friday, 22 September 2006